The chapter Motion introduces the foundational concepts of kinematics—the study of motion without considering its causes. Students learn to describe motion using terms like distance, displacement, speed, velocity, and acceleration. It explores uniform and non-uniform motion, along with graphical representation (distance-time and velocity-time graphs). The chapter also derives and applies the three equations of motion using graphical and algebraic methods and introduces the concept of uniform circular motion.
II. Key Concepts Covered:
Concept
Description
Motion
A body is in motion if it changes its position with respect to time.
Distance vs. Displacement
Distance: Total path covered; Displacement: Straight-line change in position.
Speed vs. Velocity
Speed is scalar (no direction); velocity is vector (has direction).
Acceleration
Rate of change of velocity; can be positive (speeding up) or negative (slowing down).
Uniform Motion
Equal distances in equal intervals of time.
Non-Uniform Motion
Unequal distances in equal intervals.
Equations of Motion
v=u+atv = u + atv=u+at
s=ut+12at2s = ut + frac{1}{2}at^2s=ut+21at2
v2=u2+2asv^2 = u^2 + 2asv2=u2+2as | Graphical Representation | Distance-time & velocity-time graphs help in visual analysis of motion. | | Uniform Circular Motion | Motion along a circular path with constant speed but changing direction. |
III. Important Questions:
(A) Multiple Choice Questions (1 Mark):
The SI unit of acceleration is: a) m/s b) m/s² ✅ c) km/h d) m/s³
A body is moving with uniform velocity. Its acceleration is: a) Positive b) Negative c) Zero ✅ d) Constant
Which graph shows uniform speed? a) Curved velocity-time graph b) Sloped straight line in distance-time graph ✅ c) Horizontal distance-time graph d) Steep velocity-time curve
A car starts from rest and attains a speed of 20 m/s in 10 seconds. Its acceleration is: a) 2 m/s² ✅ b) 0.5 m/s² c) 5 m/s² d) 10 m/s²
(B) Short Answer Questions (2/3 Marks):
Define displacement and explain how it can be zero even when distance is not.
Differentiate between speed and velocity with an example.
A car travels 60 km in 2 hours. Calculate its average speed.
Draw a velocity-time graph for an object moving with uniform acceleration. – PYQ 2022
(C) Long Answer Questions (5 Marks):
Derive the three equations of motion using the graphical method.
A car accelerates from rest at 2 m/s². Find: a) Its velocity after 5 seconds b) Distance covered in 5 seconds – PYQ 2021
Explain uniform circular motion. Give two examples from daily life.
Plot a distance-time graph for: a) Uniform motion b) Non-uniform motion Explain how slope indicates speed.
(D) HOTS (Higher Order Thinking Skills):
A cyclist moves in a circular path with uniform speed. Is the motion uniform or accelerated? Justify.
Two cars start from the same point—one travels east, another north—both at 40 km/h for 2 hours. Compare distance and displacement.
IV. Key Formulas/Concepts:
Formula
Description
v=u+atv = u + atv=u+at
Final velocity after time t
s=ut+12at2s = ut + frac{1}{2}at^2s=ut+21at2
Distance covered in time t
v2=u2+2asv^2 = u^2 + 2asv2=u2+2as
Relation between velocity and displacement
Average Speed = Total DistanceTotal Timefrac{text{Total Distance}}{text{Total Time}}Total TimeTotal Distance
Speed over total journey
Acceleration = v−utfrac{v – u}{t}tv−u
Rate of change of velocity
V. Deleted Portions (CBSE 2025–2026):
No portions have been deleted from this chapter as per the rationalized NCERT textbooks (2025–26).
VI. Chapter-Wise Marks Bifurcation (Estimated – CBSE 2025–2026):